25x=4x^(1/3)

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Solution for 25x=4x^(1/3) equation:


x in (-oo:+oo)

25*x = 4*x^(1/3) // - 4*x^(1/3)

25*x-(4*x^(1/3)) = 0

25*x-4*x^(1/3) = 0

t_1 = x^(1/3)

25*t_1^3-4*t_1^1 = 0

25*t_1^3-4*t_1 = 0

t_1*(25*t_1^2-4) = 0

25*t_1^2 = 4 // : 25

t_1^2 = 4/25

t_1^2 = 4/25 // ^ 1/2

abs(t_1) = 2/5

t_1 = 2/5 or t_1 = -2/5

t_1 = 0

t_1 = 0

t_1 = 2/5

x^(1/3)-2/5 = 0

1*x^(1/3) = 2/5 // : 1

x^(1/3) = 2/5

x^(1/3) = 2/5 // ^ 3

x = 8/125

t_1 = -2/5

x^(1/3)+2/5 = 0

1*x^(1/3) = -2/5 // : 1

x^(1/3) = -2/5

( -2/5 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 0

x^(1/3)+0 = 0

x^(1/3) = 0

1*x^(1/3) = 0 // : 1

x^(1/3) = 0

x = 0

x in { 8/125, 0 }

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